Nuklon

Nuklon (latinçä nukleus - töş) protonnar häm neytronnar ğomumi ataması.
Elektromagnit tä'sir iteşü qaraşı buyınça proton häm neytron - törle kisäkçeklär, çönki neytron qorğısız kisäkçe.
Läkin atom-töşe öçen iñ möhim köçle tä'sir iteşü buyınça proton häm neytron bik oxşaş, şuña kürä alar törle izospin proyektsiäse belän nuklon ike xaläte bulıp sanala.
Nuklonnar barionnar ğailälegenä qarıylar, iñ ciñel barionnar bulıp toralar.
Nuklon üzlekläre
| İsem | Bilge | Massa, Mev | Tormış waqıtı | Elektr qorğısı | İzospin proektsiäse | Kvark tözeleşe |
|---|---|---|---|---|---|---|
| Neytron | n0 | 939,565 | 886 sek | 0 | −1/2 | udd |
| Proton | p+ | 938,2726 | > 2,9×1029 yıl | +1 | +1/2 | uud |

Ädäbiät
- Christine A. Aidala, Steven D. Bass, Delia Hasch, Gerhard K. Mallot The spin structure of the nucleon (англ.) // Rev. Mod. Phys.. — 2013. — Vol. 85. — P. 655—691. — DOI:10.1103/RevModPhys.85.655 — arΧiv:1209.2803
Content Disclaimer
Informasi ini disarikan dari Wikipedia dan disajikan kembali untuk tujuan edukasi. Konten tersedia di bawah lisensi CC BY-SA 3.0. Kami tidak bertanggung jawab atas ketidakakuratan data yang bersumber dari kontribusi publik tersebut.
- The information displayed on this website is sourced in part or in whole from Wikipedia and has been adapted for the purpose of restating it. We strive to provide accurate and relevant information, however:
- There is no guarantee of absolute accuracy. Wikipedia is an open, collaborative project that can be edited by anyone, so information is subject to change.
- It is not intended to constitute professional advice. The content displayed is for informational and educational purposes only. For important decisions (e.g., medical, legal, or financial), please consult a professional.
- Content copyright. Wikipedia is licensed under the Creative Commons Attribution-ShareAlike License (CC BY-SA). This means that content may be reused with appropriate attribution and shared under a similar license.
- Responsible use. Any risk arising from the use of information from this website is entirely the responsibility of the user.