1998 Kremlin Cup – Women's doubles

Women's doubles
1998 Kremlin Cup
1997 Champions	Arantxa Sánchez Vicario Natasha Zvereva
Final
Champions	Mary Pierce Natasha Zvereva
Runners-up	Lisa Raymond Rennae Stubbs
Score	6–3, 6–4
Details
Seeds	4
Events
Singles men women Doubles men women
← 1997 · Kremlin Cup · 1999 →

Arantxa Sánchez-Vicario and Natasha Zvereva were the defending champions but only Zvereva competed that year with Mary Pierce.

Pierce and Zvereva won in the final 6–3, 6–4 against Lisa Raymond and Rennae Stubbs.

Champion seeds are indicated in bold text while text in italics indicates the round in which those seeds were eliminated.

1. Lisa Raymond / Rennae Stubbs (final)
2. Conchita Martínez / Patricia Tarabini (quarterfinals)
3. Katrina Adams / Larisa Neiland (first round)
4. Elena Likhovtseva / Ai Sugiyama (first round)

	First round							Quarterfinals							Semifinals							Final
	1	L Raymond R Stubbs	6	6
		I Spîrlea C Vis	0	3				1	L Raymond R Stubbs	6	6
		M Bollegraf E Tatarkova	6	6					M Bollegraf E Tatarkova	3	2
		S Appelmans A Huber	3	0											1	L Raymond R Stubbs	6	7
	3	K Adams L Neiland	3	3											Q	C Black I Selyutina	3	5
	Q	C Black I Selyutina	6	6				Q	C Black I Selyutina	6	6
		J Halard-Decugis C Rubin	4	0	r				C Cristea C Morariu	4	0
		C Cristea C Morariu	6	1																		1	Lisa Raymond Rennae Stubbs	3	4
		A Kournikova M Seles	6	3	6																		Mary Pierce Natasha Zvereva	6	6
		B Schett P Schnyder	4	6	3				A Kournikova M Seles	w/o
		S Williams V Williams	3	7	7				S Williams V Williams
	4	E Likhovtseva A Sugiyama	6	5	6											A Kournikova M Seles	4	1
	WC	E Makarova N Petrova	0	6												M Pierce N Zvereva	6	6
		M Pierce N Zvereva	6	7					M Pierce N Zvereva	6	6
		S Farina K Habšudová	4	4				2	C Martínez P Tarabini	2	2
	2	C Martínez P Tarabini	6	6

• 1998 Kremlin Cup Women's Doubles Draw