ds 146.6.203.178 (talk) 12:59, 31 March 2009 (UTC)

chris: this thing

${\displaystyle {\hat {j}}\partial \beta \Omega \chi }$ ${\displaystyle {\hat {j}}\partial \beta \theta \chi }$

${\displaystyle \int _{a}^{b}f(x)dx=F(x)|_{x=a}^{x=b}}$

${\displaystyle \int _{a}^{b}f(x)dx=F(x)|_{x=a}^{x=b}}$

Failed to parse (unknown function "\cursive"): {\displaystyle \cursive{EBHM}}

int main()
int main()
int main()
int main()
int main()
int main()
int main()
int main()
int main()
int main()
int main()
int main()
int main()
int main()

editing math formulas
adding images
mathml chars
math toys
watchlist
Benford's Law

${\displaystyle \phi (t)=\angle {x_{a}(t)}}$

${\displaystyle I_{R-G}={{qAn_{i} \over 2\tau _{0}}W}{(e^{qV_{A}/kT}) \over ({1+{{V_{bi}-V_{A}} \over {kT/q}}{{\sqrt {\tau _{n}\tau _{p}}} \over 2\tau _{0}}{e^{qV_{A}/2kT}}})}}$

${\displaystyle e^{i\pi }+1=0\,}$
${\displaystyle S=\sum _{m=1}^{\infty }{\sum _{n=1}^{\infty }{mn^{2} \over 2^{n}(n2^{m}+m2^{n})}}}$
${\displaystyle S={1 \over 2}\left(\sum _{m=1}^{\infty }{\sum _{n=1}^{\infty }{mn^{2} \over 2^{n}(n2^{m}+m2^{n})}}+\sum _{m=1}^{\infty }{\sum _{n=1}^{\infty }{mn^{2} \over 2^{n}(n2^{m}+m2^{n})}}\right)}$
${\displaystyle S={1 \over 2}\left(\sum _{m=1}^{\infty }{\sum _{n=1}^{\infty }{m^{2}n \over 2^{m}(n2^{m}+m2^{n})}}+\sum _{m=1}^{\infty }{\sum _{n=1}^{\infty }{mn^{2} \over 2^{n}(n2^{m}+m2^{n})}}\right)}$

${\displaystyle S={1 \over 2}\sum _{m=1}^{\infty }{\sum _{n=1}^{\infty }{{m^{2}n \over 2^{m}(n2^{m}+m2^{n})}+{mn^{2} \over 2^{n}(n2^{m}+m2^{n})}}}}$
${\displaystyle S={1 \over 2}\sum _{m=1}^{\infty }{\sum _{n=1}^{\infty }{m^{2}n2^{n}+n^{2}m2^{m} \over 2^{m}2^{n}(n2^{m}+m2^{n})}}}$
${\displaystyle S={1 \over 2}\sum _{m=1}^{\infty }{\sum _{n=1}^{\infty }{mn \over 2^{m}2^{n}}}={1 \over 2}\left(\sum _{m=1}^{\infty }{m \over 2^{m}}\right)^{2}}$
${\displaystyle \sum _{m=1}^{\infty }{m \over 2^{m}}=2}$
${\displaystyle {S=2}}$

${\displaystyle \displaystyle y(t)=\cos(2\pi (f_{0}t+{\beta \over 2}t^{2}+\phi _{0}))}$

${\displaystyle \mathbb {PNZQARCHO} \ }$

${\displaystyle \sum _{x=0}^{100}f(x)}$...

${\displaystyle {\frac {df(t)}{dx}}}$...

${\displaystyle x^{2_{3}}}$...

${\displaystyle \oint T_{i}(n)a\,dn}$...

${\displaystyle \int T_{i}(n)a\,dn\,}$...

∫₀f(x) dx...

${\displaystyle \sum _{t=i}N(a)\,}$...

${\displaystyle ax^{2}+bx+c=0}$...

${\displaystyle ax^{2}+bx+c=0\,}$

${\displaystyle \int _{a}^{b}f(x)dx=F(x)|_{x=a}^{x=b}}$

bb: ${\displaystyle \mathbb {ABCDEFGHIJKLMNOPQRSTUVWXYZ} }$
frak: ${\displaystyle {\mathfrak {1234567890abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ}}}$
cal: ${\displaystyle {\mathcal {ABCDEFGHIJKLMNOPQRSTUVWXYZ}}}$
bb: ${\displaystyle \mathbb {1234567890abcdefghijklmnopqrstuvwxyz} }$
cal: ${\displaystyle {\mathcal {1234567890abcdefghijklmnopqrstuvwxyz}}}$
symb: ${\displaystyle \int \coprod }$${\displaystyle {\begin{matrix}\int \end{matrix}}}$${\displaystyle {\begin{matrix}\coprod \end{matrix}}}$
cal not in symb: ${\displaystyle {\mathcal {45apqsx}}}$

${\displaystyle {\mathcal {45}}}$, \mathcal{45} should be \bigtriangleup and \bigtriangledown
\mathcal{6} puts a slash through the next character
\mathcal{7} puts something through the next character
${\displaystyle {\mathcal {a}}}$, \mathcal{a} should be \dashv
\mathcal{p} puts a surd below the textline, should be \surd
\mathcal{x} = §

Latex symbols with no mirror counterparts: \Lleftarrow \multimap \rightsquigarrow

test test test

test test test

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this is a long line this is a long line this is a long line this is a long line this is a long line this is a long line this is a long line this is a long line this is a long line this is a long line this is a long line this is a long line this is a long line this is a long line this is a long line this is a long line this is a long line this is a long line this is a long line this is a long line