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Can the Subtracter (electronics) be explained with circuits and truth tables the same way as the Adder (electronics)(http://en.wikipedia.org/wiki/Full_adder)?

a subtractor is basically just an adder with one input inverted and the first carry in set to 1 rather than 0.

the truth table for full subtractor is not correct; read this => http://www.doc.ic.ac.uk/~dfg/hardware/HardwareLecture13.pdf 60.48.175.38 (talk) 18:57, 26 September 2011 (UTC)[reply]

Note, the full substractor graphic is wrong. The first inversor goes in the A imput. If the subtrahend is 0 and the minuend is 1, it triggers the borrow out. — Preceding unsigned comment added by Mbertelotti (talk • contribs) 20:42, 22 April 2013 (UTC)[reply]

The diagram should be replaced such that the X input is the minuend and Y is the subtrahend. Doing it this way would make the diagram consistent with the article and the following explanation unnecessary:

An important point worth mentioning is that the half subtractor diagram aside implements ${\displaystyle Y-X}$ and not ${\displaystyle X-Y}$ since ${\displaystyle B_{\text{out}}}$ on the diagram is given by

${\displaystyle B_{\text{out}}=X\cdot {\overline {Y}}}$.

This is an important distinction to make since subtraction itself is not commutative, but the difference bit ${\displaystyle D}$ is calculated using an XOR gate which is commutative.

We could still have a footnote that says whichever input is inverted is the minuend. --Usability (talk) 07:40, 1 November 2015 (UTC)[reply]